marcus22
Junior Member
It means that some of your regulator output is being wasted instead of charging the battery. The difference between a battery not being charged at all (12.70 volts) and the battery being overcharged (14.70 volts) is only 2 volts. It's easy to think it's 12 volts and not just 2 volts, but it's just 2 volts..
So if you measure a voltage drop of just .50 volts, that really represents 25% of the stator's total output being wasted. That means the stator & regulator needs to work overtime just to keep up with the loses of poor connections.. The regulator and stator will now be on overtime and will run hotter than they should. If your lucky, a diode will open when the regulator finally gives up. But if it shorts, the stator is 30 minutes from its death.
that makes total sense! Thank you. so i need to fix the charging problem before I test the voltage drop from the regulator to the batt. right?